Question

what is the average rate of change in elevation for the road over the first 4km? remember that f(x) stands for hundreds of feet. include units in your answer.

Answer 1

Answer:

3 hundred ft / km

Explanation:

The average rate of change for a function is

$\frac{f(a)-f(b)}{a-b}$

in our case this is

$\begin{gathered} \frac{f(4)-f(0)}{4-0} \\ \end{gathered}$

now

f(4) = 19 hundred ft

f(0) = 7 hundred ft

therefore,

$\frac{19-7}{4-0}$$=3(\text{hundred ft/km)}$

which is our answer!