Question

Simplify: 15-(-10)+(-8)-12+(-2)

Answer 1

Solution:

Given:

$15-(-10)+(-8)-12+(-2)$

Since we have multiple operations, we solve using PEMDAS or BODMAS.

where;

$\begin{gathered} P=\text{Parentheses} \\ E=Exponents \\ M=\text{Multiplication} \\ D=\text{Division} \\ A=\text{Addition} \\ S=\text{Subtraction} \end{gathered}$

$\begin{gathered} B=\text{Bracket} \\ O=\text{Order} \\ D=\text{Division} \\ M=\text{Multiplication} \\ A=\text{Addition} \\ S=\text{Subtraction} \end{gathered}$

From the above order, we solve the parentheses (or brackets first) using the directed number multiplication of signs.

Recall that;

$\begin{gathered} +\times+=+ \\ -\times-=+ \\ +\times-=- \\ -\times+=- \end{gathered}$

Hence,

$\begin{gathered} 15-(-10)+(-8)-12+(-2) \\ =15+10-8-12-2 \\ =25-8-12-2 \\ =17-12-2 \\ =5-2 \\ =3 \end{gathered}$

Therefore,

$15-(-10)+(-8)-12+(-2)=3$

The answer is 3.