if a baseball player got 69 hits out of 100 at-bats what fraction and what percentage of times at a bad did the player and not get a hit? choose 2 answers

EXPLANATION:
Given;
We are told that a baseball player got 69 hits out of 100 at-bats.
Required;
We are required to calculate the:
(1) Fraction
(2) Percentage
Of times that the player did not get a hit.
Step-by-step solution;
To solve this math problem, we would have to determine how many times out of a hundred that the player DID NOT get a hit.
This is shown below;
[tex]\begin{gathered} Total=100 \\ Hits=69 \\ Missed=31 \end{gathered}[/tex]The number of misses as a fraction would be;
[tex]Fraction=\frac{misses}{total}[/tex][tex]Fraction=\frac{31}{100}[/tex][tex]Percentage=\frac{31}{100}\times\frac{100}{1}[/tex][tex]Percentage=31\%[/tex]Therefore;
ANSWER:
[tex]\begin{gathered} (A) \\ \frac{31}{100} \end{gathered}[/tex][tex]\begin{gathered} (C) \\ 31\% \end{gathered}[/tex]