Solution:
Let x be the number of nickels and y be the number of dimes in Carolyn's purse.
There is $3.25 in her purse in nickes and dimes. T
Recall that;
[tex]\begin{gathered} 1\text{ dime}=\text{ \$}0.1 \\ \\ 1\text{ nickel }=\text{ \$}0.05 \end{gathered}[/tex]Thus;
[tex]0.05x+0.1y=3.25..........equation1[/tex]Also, the number of nickels is five less than three times the number of dimes. Thus;
[tex]x=3y-5...........equation2[/tex]Substitute equation2 in equation1;
[tex]\begin{gathered} 0.05(3y-5)+0.1y=3.25 \\ \\ 0.15y-0.25+0.1y=3.25 \\ \\ 0.25y=3.25+0.25 \\ \\ y=\frac{3.5}{0.25} \\ \\ y=14 \end{gathered}[/tex]Substitute the value of y in equation2;
[tex]\begin{gathered} x=3(14)-5 \\ \\ x=37 \end{gathered}[/tex]Hence, there are 37 nickels and 14 dimes in Carolyn's purse.