Answer:
h(-8) = -40
Explanation:
Given the function:
[tex]h(x)=\frac{1}{4}x^2+7x[/tex]To evaluate the value of h(-8), we substitute -8 for x in h(x).
[tex]\begin{gathered} h(-8)=\frac{1}{4}(-8)^2+7(-8) \\ =(\frac{1}{4}\times64)-56 \\ =16-56 \\ =-40 \end{gathered}[/tex]
