find the arean of the regular polygon. round your answer to the nearest tenth

The area of the hexagon is given as:
[tex]A=\frac{1}{2}Pa[/tex]where P is the perimeter and a is the apothem.
Now, we need to notice that the we have the following triangle:
and we notice that x is half the length of each side of the hexagon.
From this triangle we notice that:
[tex]\begin{gathered} \tan 60=\frac{6}{x} \\ x=\frac{6}{\tan60} \\ x=\frac{6}{\sqrt[]{3}} \\ x=\frac{6\sqrt[]{3}}{3} \end{gathered}[/tex]Once we found x that means that each side has length :
[tex]\frac{12\sqrt[]{3}}{3}[/tex]Now, the perimeter is:
[tex]6\cdot\frac{12\sqrt[]{3}}{3}=24\sqrt[]{3}[/tex]Plugging this values and the apothem in the area formula we have that:
[tex]A=\frac{1}{2}(24\sqrt[]{3})(6)=72\sqrt[]{3}=124.7[/tex]Therefore the area is 124.7 squared inches