Given data
*The given resistor is R = 1 Kohm = 1 ×10^3 ohms
*The given voltage is V = 15 V
The formula for the power dissipation is given as
[tex]P=\frac{V^2}{R}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} P=\frac{(15)^2}{(1\times10^3)} \\ =0.225\text{ W} \end{gathered}[/tex]