I you could just give me the answer that would be great no explanation needed:) I will give you a highesr rating if you do thank you this is just extra credit

I you could just give me the answer that would be great no explanation needed I will give you a highesr rating if you do thank you this is just extra credit class=

Respuesta :

In order to calculate the length of segment EF, we can use the formula of the distance between two points (x1, y1) and (x2, y2):

[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Since the coordinates of E are (-3, 1) and F are (-1, -2), we have:

[tex]\begin{gathered} d_{EF}=\sqrt[]{(-1-(-3))^2+(-2-1)^2_{}} \\ d_{EF}=\sqrt[]{(2)^2+(-3)^2} \\ d_{EF}=\sqrt[]{4+9} \\ d_{EF}=\sqrt[]{13} \\ d_{EF}=3.6 \end{gathered}[/tex]

So the length of EF is 3.6 units.

RELAXING NOICE
Relax