if this is question can be answered as soon as possible that would be spending

For this problem we are given the dimensions of a square pyramid and we need to determine its surface area.
The surface area of the pyramid can b found with the following expression:
[tex]A_{surface}=A_{base}+4\cdot A_{lateral}[/tex]Where Abase is the area of the square and Alateral is the area of a triangular face. We have:
[tex]\begin{gathered} A_{base}=3\cdot3=9\text{ square inches}\\ \\ A_{lateral}=\frac{3\cdot5}{2}=7.5\text{ square inches} \end{gathered}[/tex]The surface area is:
[tex]A_{surface}=9+4\cdot7.5=9+30=39\text{ square inches}[/tex]The correct answer is C.