Answer
He invested
$111,000 at 9%
$368,000 at 12%
Explanation
Let the amount the actor invested at 9% simple interest be x dollars
Let the amount the actor invested at 12% simple interest be y dollars
The amount made from the x dollars will be
0.09 × x = (0.09x) dollars
The amount made from the y dollars will be
0.12 × y = (0.12y) dollars
Total amount made from the investments = 54,150 dollars
0.09x + 0.12y = 54,150
Then we are told that the amount invested at 12% is 35,000 more than three times the amount invested at 9%
y = 3x + 35,000
We can write these two equations together now
0.09x + 0.12y = 54,150
y = 3x + 35,000
0.09x + 0.12(3x + 35,000) = 54,150
0.09x + 0.36x + 4,200 = 54,150
0.45x + 4,200 = 54,150
0.45x = 54,150 - 4,200
0.45x = 49,950
Divide both sides by 0.45
(0.45x/0.45) = (49,950/0.45)
x = 111,000
y = 3x + 35,000
y = 3 (111,000) + 35,000
y = 333,000 + 35,000
y = 368,000
Hope this Helps!!!
