Question

Given the table of values above, find a linear equation for y in terms of t.

Answer 1

Given:

find: linear equation for y in terms of t.

Explanation:

$\begin{gathered} m=\frac{\Delta Y}{\Delta X} \\ =\frac{6}{8}&\frac{9}{12} \end{gathered}$$\begin{gathered} y=mt+c \\ y=\frac{3}{4}t+c \\ 1=\frac{3}{4}(16)+c \\ c=-11 \end{gathered}$

so the equation becomes

$\begin{gathered} y=\frac{3}{4}t-11 \\ 4y=3t-44 \end{gathered}$

Final answer: the required equation is 4y=3t-44.