Respuesta :

The given function is,

[tex]f(x)=2x^2+32-72[/tex]

The function can be rewritten with the GCF removed,

[tex]f(x)=2(x^2+16-36)[/tex]

The GCF is 2.

The value of a,b and c are,

[tex]\begin{gathered} a=2 \\ b=0 \\ c=-40 \end{gathered}[/tex]

The factored form is ,

[tex]\begin{gathered} 2x^2-40 \\ =2(x^2-20) \\ =2(x+2\sqrt[]{5})(x-2\sqrt[]{5)} \end{gathered}[/tex]

The factor pair is,

[tex]\begin{gathered} a\times c=2\times(-40) \\ =-80 \end{gathered}[/tex]

The sum of factor pair is,

[tex]2\sqrt[]{5}-2\sqrt[]{5}=0[/tex]

The sum of factor pair is -b/a.

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