Question

What depth of sea water (in m) creates a pressure of 1.83 atm?

Answer 1

Given:

Pressure = 1.83 atm

Let's determine the depth of sea water that creates the given pressure.

Apply the formula for pressure on a liquid:

$P=\rho gh$

Where:

P is the pressure in Pa.

Where:

1 atm = 101325 Pa

1.83 atm = 1.83 x 101325 = 185424.8 Pa

ρ is the density of sea water = 1000 kg/m³

g is acceleration due to gravity = 9.8 m/s²

h is the depth.

Rewrite the formula for h and solve:

$\begin{gathered} h=\frac{P}{\rho g} \\ \\ h=\frac{185424.8}{1000*9.8} \\ \\ h=\frac{185424.8}{9800} \\ \\ h=18.92\text{ m} \end{gathered}$

Therefore, the depth of sea water which creates the pressure given is 18.92 m

ANSWER:

18.92 m