Respuesta :

We are given:

[tex]\begin{gathered} f(-2)\text{ = -3 and} \\ g(-2)\text{ = 5} \end{gathered}[/tex]

(a) (f + g)(-2):

Recall that:

[tex](f+g)(x)\text{ = f(x) + g(x)}[/tex]

Applying this:

[tex]\begin{gathered} (f+g)(-2)\text{ = f(-2) + g(-2)} \\ =\text{ -3 + 5} \\ =\text{ 2} \end{gathered}[/tex]

Hence: (f + g)(-2) = 2

(b) (f/g)(-2):

Recall that:

[tex](\frac{f}{g})(x)\text{ = }\frac{f(x)}{g(x)}[/tex]

[tex]\begin{gathered} (\frac{f}{g})(-2)\text{ = }\frac{f(-2)}{g(-2)} \\ =\text{ }\frac{-3}{5} \\ =\text{ -}\frac{3}{5} \end{gathered}[/tex]

Hence, (f/g)(-2) = -3/5

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