Question

-Solve this system of equations byusing the elimination method.-3x + 8y = 43x – 2y = 8([?], []).-=The ordered pair of solutionsis written in the format (x, y).

Answer 1

Answer: (4,2)

Given:

$\begin{gathered} -3x+8y=4 \\ 3x-2y=8 \end{gathered}$

With this given, we can first eliminate -3x and 3x and solve for y first.

$\begin{gathered} -3x+8y=4 \\ 3x-2y=8 \\ ========== \\ 8y=4 \\ -2y=8 \\ ----- \\ 6y=12 \\ y=2 \end{gathered}$

Then, we can now use either of the equations to solve for x. Let us try using the first equation:

$\begin{gathered} -3x+8y=4 \\ -3x+8\lparen2)=4 \\ -3x=4-16 \\ -3x=-12 \\ x=4 \end{gathered}$

Therefore, the solution to this system of equations is (4,2)