Respuesta :

hello

to solve this question, we need to use a standard normal table (z)

out z-value give = -1.27

this is equivalent to 0.4032

note, i approximated 1.27 to 1.3 and the z-value for -1.3 = 0.4032

to compensated tp the other side of the graph, we should add 0.5 to 0.4032

[tex]0.4032+0.5=0.9032[/tex]

the area under z = -1.27 is equal to 0.9032 square units or 90.32%

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