Remember that
The surface area of the given figure, is equal to the area of all its six faces
step 1
Find out the area of the base
The base is a rectangle of 19 in x 22 in
[tex]A_1=19*22=418\text{ in}^2[/tex]
step 2
Find out the area of the top
The top is a rectangle of 13 in x 22 in
[tex]A_2=13*22=286\text{ in}^2[/tex]
step 3
Find out the area of the two trapezoidal faces
[tex]A_{3-4}=2[\frac{1}{2}(19+13)(14)]=448\text{ in}^2[/tex]
step 4
Find out the area of the two lateral rectangular faces
[tex]A_{5-6}=2[22*16]=704\text{ in}^2[/tex]
therefore
The surface area is equal to
SA=418+286+448+704
SA=1,856 in2
