Respuesta :

[tex]4x^2-27x+18[/tex]

We have the above equation, this is a quadratic polynomial, which is a polynomial with two real roots (two x-axis crossings), therefore x has two possible solutions.

Now, let's factor this equation and find the values for x.

[tex]\begin{gathered} (4x^2-3x)+(-24x+18) \\ x(4x-3)+6(4x-3) \end{gathered}[/tex]

Now, we factor in the common term 4x-3.

[tex](4x-3)(x-6)[/tex]

Now, let's solve for the two values of x

[tex]\begin{gathered} x-6=0 \\ x=6 \end{gathered}[/tex][tex]\begin{gathered} 4x-3=0 \\ 4x=3 \\ x=\frac{3}{4}=0.75 \end{gathered}[/tex]

In conclusion, x can take the value of x = 6 or x = 0.75

In the following graph we can see this:

Ver imagen YedidyaZ768218
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