Hello! I need some assistance with this homework question for precalculus, please?HW Q28

To evaluate the given expression, simply convert the expression to logarithmic form.
[tex]\begin{gathered} y=3^{log_36} \\ Convert. \\ \begin{equation*} log_36=log_3y \end{equation*} \end{gathered}[/tex]Based on the conversion, we can see that the value of y is 6. Hence, the value of 3 raised to the power of log 6 base 3 is 6.
[tex]3^{log_36}=6[/tex]The answer is 6.