Use the sum and difference identities to rewrite the following expression as a trigonometric function of a single number.cos(15") cos(15) – sin(15") sin(15)

Solution:
From the sum and difference identities expressed as
[tex]\begin{gathered} \sin (A+B)=\sin A\cos B+\sin B\cos A\text{ ---- equation 1} \\ \sin (A-B)=\sin A\cos B-\sin B\cos A\text{ ----- equation 2} \\ \text{cos}(A+B)=\cos A\cos B-\sin A\sin B\text{ ------ equation 3} \\ \text{cos}(A-B)=\cos A\cos B+\sin A\sin B\text{ ------ equation }4 \end{gathered}[/tex]Given:
[tex]\cos (15)\cos (15)-\sin (15)\sin (15)[/tex]The above expression satisfies equation 3, where
[tex]\begin{gathered} A=15, \\ B=15 \end{gathered}[/tex]Thus,
[tex]\begin{gathered} \cos (15)\cos (15)-\sin (15)\sin (15)=\cos (15+15) \\ =\cos (30) \end{gathered}[/tex]Hence, the expression is simplified to be
[tex]\cos (30)[/tex]