Using Cramer's rule in solving systems.
[tex]\begin{gathered} a_1x+b_1y=c_1 \\ a_2x+b_2y=c_2 \end{gathered}[/tex]The solution for x and y are :
[tex]\begin{gathered} x=\frac{b_2c_1-b_1c_2}{a_1b_2_{}-_{}a_2b_1} \\ \\ y=\frac{a_1c_2-a_2c_1}{a_1b_2_{}-a_2b_1} \end{gathered}[/tex]From the problem, we have two equations :
[tex]\begin{gathered} x-6y=2 \\ 12x+7y=-55 \end{gathered}[/tex]From the equations, the values are :
[tex]\begin{gathered} a_1=1,b_1=-6,c_1=2 \\ a_2=12,b_2=7,c_2=-55 \end{gathered}[/tex]Using the formula above, the values of x and y are :
[tex]\begin{gathered} x=\frac{b_2c_1-b_1c_2}{a_1b_2-_{}a_2b_1}=\frac{7(2)-(-6)(-55)}{1(7)-12(-6)} \\ x=\frac{14-330}{7+72} \\ x=-4 \\ \\ y=\frac{a_1c_2-a_2c_1}{a_1b_2-a_2b_1}=\frac{1(-55)-12(2)}{1(7)-12(-6)} \\ y=\frac{-55-24}{7+72} \\ y=-1 \end{gathered}[/tex]The solution set is One solution. (-4, -1)