Question

the equation of line u is y=3/8×+6. line v is perpendicular to u. what is the slope of v?

Answer 1

The given equation is

$y=\frac{3}{8}x+6$

We know that line v is perpendicular to u (the given equation).

The definition for perpendicularity in this case is

$m_u\cdot m_v=-1$

Additionally, from the given equation, we know that the slope of line u is 3/8. Using the perpendicularity definition, we have

$\begin{gathered} \frac{3}{8}\cdot m_v=-1 \\ m_v=-\frac{8}{3} \end{gathered}$

Therefore, the slope of line v is -8/3.