Question

Given the equation of a line 2x+4y=16, determine the following: What’s the slope of the line?M=What is the y-intercept? Enter your answer as an ordered pair in the form (x,y)Y-intercept:

Answer 1

Given:

The equation of a line is given as 2x+4y=16.

The objective is, to find the slope of the line and to find the y-intercept.

Explanation:

To find slope:

The general formula of the slope-intercept form of a straight line is,

$y=mx+b\text{ . . . . .(1)}$

Here, m represents the slope of the equation, and b represents the y-intercept.

The given equation can be written in the slope-intercept form as,

$\begin{gathered} 4y=-2x+16 \\ y=\frac{-2x}{4}+\frac{16}{4} \\ y=-\frac{1}{2}x+4\text{ . . . . .(2)} \end{gathered}$

By comparing equation (2) with equation (1),

$m=-\frac{1}{2}$

To find the y-intercept:

By comparing equation (2) with equation (1),

$b=4$

Hence, the slope of the straight line is (-1/2) and the y-intercept