Respuesta :

Answer:

Given equation of a parabola is,

[tex]f(x)=x^2-2x+3[/tex]

To find the vertex of the parabola.

we know that,

Equation of the parabola is,

[tex]y=a(x-h)^2+k[/tex]

where (h,k) is the vertex of the parabola.

we know that f(x)=y, the equation becomes,

[tex]y=x^2-2x+3[/tex]

To rewrite the above equation in the required format, adding and subtracting by1, we get

[tex]y=x^2-2x+1-1+3[/tex][tex]y=(x-1)^2+2[/tex]

we get the vertex as (1,2)

Vertex is (1,2)

y-intercept:

when x=0, we get y=3

y-intercept is y=3.

Answer is:

Vertex is (1,2) an y-intercept is y=3.

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