identify the vertex, and the Y-intercept then click another point of parabola

Answer:
Given equation of a parabola is,
[tex]f(x)=x^2-2x+3[/tex]To find the vertex of the parabola.
we know that,
Equation of the parabola is,
[tex]y=a(x-h)^2+k[/tex]where (h,k) is the vertex of the parabola.
we know that f(x)=y, the equation becomes,
[tex]y=x^2-2x+3[/tex]To rewrite the above equation in the required format, adding and subtracting by1, we get
[tex]y=x^2-2x+1-1+3[/tex][tex]y=(x-1)^2+2[/tex]we get the vertex as (1,2)
Vertex is (1,2)
y-intercept:
when x=0, we get y=3
y-intercept is y=3.
Answer is:
Vertex is (1,2) an y-intercept is y=3.