SOLUTION
Explanation:
To represent vector in trigonometric form; first of obtain the magnitude and direction of the vector.
[tex]W=(-21,\text{ -20})[/tex]
[tex]\begin{gathered} The\text{ magnitude of W is;} \\ \sqrt{(-21)^2+(-20)^2}=29 \end{gathered}[/tex][tex]\begin{gathered} The\text{ direction }\theta,\text{ is;} \\ tan\theta=\frac{w_y}{w_x} \\ tan\theta=\frac{-20}{-21} \\ \theta=tan^{-1}(\frac{20}{21}) \\ The\text{ direction =180+}43.6=223.6\degree \end{gathered}[/tex][tex]The\text{ trigonometric form is:}[/tex][tex]W=29(cos223.603i,\text{ sin223.603j})[/tex]
Final answer:
