Which choice below is most likely the value of the mean of the data set shown in the histogram above?

Answer:
9.86
Explanation:
To estimate the mean from the histogram, first, find the total frequency.
[tex]\text{Total Frequency}=8+4+7+1+6+2=28[/tex]Next, calculate the midpoint of each of the bars.
[tex]\begin{gathered} \frac{0+4}{2}=\frac{4}{2}=2 \\ \frac{4+8}{2}=\frac{12}{2}=6 \\ \frac{8+12}{2}=\frac{20}{2}=10 \\ \frac{12+16}{2}=\frac{28}{2}=14 \\ \frac{16+20}{2}=\frac{36}{2}=18 \\ \frac{20+24}{2}=\frac{44}{2}=22 \end{gathered}[/tex]Multiply the midpoint of each bar by their respective frequencies; then find the total.
[tex]\begin{gathered} 2\times8=16 \\ 6\times4=24 \\ 10\times7=70 \\ 14\times1=14 \\ 18\times6=108 \\ 22\times2=44 \\ \text{Total}=16+24+70+14+108+44=276 \end{gathered}[/tex]Finally, divide the total obtained by the total frequency.
[tex]\text{Mean}=\frac{276}{28}=9.86[/tex]The estimated mean from the histogram is 9.86.