2 Solve the equation tan²B = 1 given that 0

Answer:
β = π/4, 3π/4
Explanation:
If tan²β = 1, we can solve the equation finding the square root, so
[tex]\begin{gathered} \tan \beta=\pm\sqrt[]{1} \\ \tan \beta=1\text{ or tan}\beta\text{ = -1} \end{gathered}[/tex]Now, we know that tanβ = 1 if β = π/4 y tanβ = -1 if β = 3π/4.
Therefore, the answers are:
β = π/4, 3π/4