When a new charter school opened in 1995, there were 370 students enrolled. Write a formula for the equation N, representing the number of students attending this charter school t years after 1995, assuming that the student population:

ANSWER:
[tex]\begin{gathered} N=370+40t \\ \\ N=370-32t \\ \\ N=370+22t \\ \\ N=370-12t \\ \\ N=370 \\ \\ N=370+20t \end{gathered}[/tex]STEP-BY-STEP EXPLANATION:
Given: Initial number = 370 students.
We can determine in each case taking into account that it would be a rate (that is, a slope) that is added to the equation.
Therefore:
Increased by 40 students per year:
[tex]N=370+40t[/tex]Decreased by 40 students per year:
[tex]N=370-32t[/tex]Increased by 44 students every 2 years:
[tex]\begin{gathered} N=370+\frac{44t}{2} \\ N=370+22t \end{gathered}[/tex]Decreased by 48 students every 4 years:
[tex]\begin{gathered} N=370-\frac{48t}{4} \\ N=370-12t \end{gathered}[/tex]Remained constant:
[tex]N=370[/tex]Increased by 10 students every semester:
[tex]\begin{gathered} N=370+2\cdot10t \\ N=370+20t \end{gathered}[/tex]