If the m angle 1 is (6x-2) and then the m angle 3 is (10x-30) the find the measure of angle 1

Answer:
Explanation:
Given:
m<1= 6x-2
m<3 = 10x-30
Based on the given figure, angles 1 and 3 are vertical, so they are equal. Vertical angles are angles opposite each other and are always congruent.
So,
m<1=m<3
We plug in what we know.
[tex]\begin{gathered} m<1=m<3 \\ 6x-2\text{ = 10x-30} \\ \text{Simplify and rearrange} \\ 10x-6x=-2+30 \\ 4x=28 \\ x=\frac{28}{4} \\ \text{Calculate} \\ x=7 \end{gathered}[/tex]Then, we plug in x=7 into m<1= 6x-2.
[tex]\begin{gathered} m<1=6x-2 \\ =6(7)-2 \\ =42-2 \\ m<1=40 \end{gathered}[/tex]We can also double check it on m<3. We plug in x=7 into 10x-30. So,
m<3 = 10x-30=10(7)-30 = 40°.
Therefore