Question

The solutions to 2x^2+8x+4=0 ar x=-8+32/4 choose the simplified form of these solutions.

Answer 1

Solution:

Given the equation;

$2x^2+8x+4=0$

Its solution is;

$x=\frac{-8\pm\sqrt{32}}{4}$

Now, we would simplify this as;

$\begin{gathered} x=\frac{-8\pm4\sqrt{2}}{4} \\ \\ x=\frac{4(-2\pm\sqrt{2})}{4} \\ \\ x=-2\pm\sqrt{2} \end{gathered}$

CORRECT OPTION: C