Take into account that the standard error, for a normal distribution, is given by the following expression:
[tex]SE=\frac{\sigma}{\sqrt[\placeholder{⬚}]{n}}[/tex]where,
σ: standard deviation = 0.75
n: sample = 35
By replacing the previous values into the formula for SE, you get:
[tex]SE=\frac{0.75}{\sqrt[\placeholder{⬚}]{35}}\approx0.13[/tex]Hence, the standard error is approximately 0.13