Question

find y if the line through (5,2) and (-3,y) has a slope m= -11/8.

Answer 1

$\begin{gathered} \text{slope, m = }\frac{y_2-y_1}{x_2-x_1} \\ \\ m=-\frac{11}{8},x_1=5,y_1=2,x_2=-3,y_2=y \end{gathered}$

Substituting these values, we have

$\begin{gathered} -\frac{11}{8}=\text{ }\frac{y-2}{-3-5} \\ \\ -\frac{11}{8}=\frac{y-2}{-8} \\ 8(y-2)=\text{ -8 x -11} \\ 8y-16=88 \\ 8y=88+16 \\ 8y=104 \\ y=\frac{104}{8} \\ y=13 \end{gathered}$