Question

Find the distance between (-1,0) and (4,2).4.52975.39

Answer 1

The given points are (-1,0) and (4,2).

We find the distance between these points using the following formula.

$d=\sqrt{(x_2-x_1)^2+(y_2-y_2)^2}$

Using the given points, we have

$\begin{gathered} d=\sqrt{(4-(-1))^2+(2-0)^2} \\ d=\sqrt{(4+1)^2+(2)^2} \\ d=\sqrt{(5)^2+4}=\sqrt{25+4}=\sqrt{29}\approx5.39 \end{gathered}$

Therefore, the distance between the given points is 5.39 units, approximately.