Respuesta :
daisiesThere are 3 types of flowers.
Let C denote carnations, R denotes roses and D denote daisies.
Billy's Restaurant ordered 200 flowers for Mother's Day.
Mathematically,
[tex]C+R+D=200\text{ eq. 1}[/tex]They ordered carnations of $1.50 each, roses at $5.75 each, and daisies of $2.60 each.
The total order came to $589.50.
Mathematically,
[tex]1.50C+5.75R+2.60D=589.50\text{ eq. 2}[/tex]They ordered mostly carnations, and 20 fewer roses than daisies.
Mathematically,
[tex]R=D-20\text{ eq. 3}[/tex]So, we have 3 equations and 3 unknowns.
Let us substitute eq. 3 into eq. 1
[tex]\begin{gathered} C+(D-20)+D=200 \\ C+D-20+D=200 \\ C+2D=200+20 \\ C+2D=220\text{ eq. 4} \end{gathered}[/tex]Let us substitute eq. 3 into eq. 2
[tex]\begin{gathered} 1.50C+5.75(D-20)+2.60D=589.50 \\ 1.50C+5.75D-115+2.60D=589.50 \\ 1.50C+8.35D=589.50+115 \\ 1.50C+8.35D=704.5\text{ eq. 5} \end{gathered}[/tex]So, now we have eq. 4 and eq. 5 with 2 unknowns. Let's solve them by substitution method.
Separate the variable C in eq. 4
[tex]C=220-2D[/tex]Now substitute it into eq. 5.
[tex]\begin{gathered} 1.50(220-2D)+8.35D=704.5 \\ 330-3D+8.35D=704.5 \\ 330+5.35D=704.5 \\ 5.35D=704.5-330 \\ 5.35D=374.5 \\ D=\frac{374.5}{5.35} \\ D=70 \end{gathered}[/tex]So. we got the number of Daisies that is 70.
Now substitute D = 70 into the previous equation.
[tex]\begin{gathered} C=220-2D \\ C=220-2(70) \\ C=220-140 \\ C=80 \end{gathered}[/tex]So. we got the number of Carnations that is 80.
Finally, from eq. 3 we get
[tex]\begin{gathered} R=D-20 \\ R=70-20 \\ R=50 \end{gathered}[/tex]So. we got the number of Roses that is 50.
Therefore.
Number of Carnations = 80
Number of Daisies = 70
Number of Roses = 50
Verification:
Total number of flowers should sum to 200.
80 + 70 + 50 = 200
200 = 200
Hence, we got the correct results.
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