Respuesta :

From the image given,

[tex]\begin{gathered} \theta=60^0\text{ (given)} \\ d=24\operatorname{cm}\text{ (given)} \\ r=\frac{d}{2}=\frac{24}{2}=12\operatorname{cm} \end{gathered}[/tex]

The area of the sector is given by;

[tex]\begin{gathered} A=\frac{\theta}{360}\times\pi r^2 \\ A=\frac{60}{360}\times\pi\times12^2 \\ A=\frac{8640\pi}{360} \\ A=24\pi \end{gathered}[/tex]

Therefore, the area of the sector in terms of pie is

[tex]24\pi cm^2[/tex]

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