In OC, BD is a diameter with length of 24cm andACB = 60°. Calculate the area of the sector.(In terms of pie)

From the image given,
[tex]\begin{gathered} \theta=60^0\text{ (given)} \\ d=24\operatorname{cm}\text{ (given)} \\ r=\frac{d}{2}=\frac{24}{2}=12\operatorname{cm} \end{gathered}[/tex]The area of the sector is given by;
[tex]\begin{gathered} A=\frac{\theta}{360}\times\pi r^2 \\ A=\frac{60}{360}\times\pi\times12^2 \\ A=\frac{8640\pi}{360} \\ A=24\pi \end{gathered}[/tex]Therefore, the area of the sector in terms of pie is
[tex]24\pi cm^2[/tex]