Assume that adults have IQ scores that are normally distributed with a moon of 101 and a standard deviation of 20.4. Find the probability that a randomly selectedadult has an IQ greater than 131.9. (Hint: Draw a graph.)The probability that a randomly selected adult from this group has an IQ greater than 131.9 in(Round to four decimal places as needed)correct

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The graph of this distribution is:

Now, from it we know that the probability has to be less 0.1586 but more than 0.0227.

To find the probability we have to use the z-score to transform our distribution to a standard normal distribution.

The z-score is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Then in this case we have:

[tex]\begin{gathered} z=\frac{131.9-101}{20.4} \\ z=1.5147 \end{gathered}[/tex]

Then our probability is:

[tex]P(X>131.9)=P(Z>1.5147)[/tex]

Looking on a table for the value of the probability we have that:

[tex]P(X>131.9)=P(Z>1.5147)=0.0649[/tex]

Therefore the probability is 0.0649; which is the same as 6.49%.

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