The graph of this distribution is:
Now, from it we know that the probability has to be less 0.1586 but more than 0.0227.
To find the probability we have to use the z-score to transform our distribution to a standard normal distribution.
The z-score is given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]Then in this case we have:
[tex]\begin{gathered} z=\frac{131.9-101}{20.4} \\ z=1.5147 \end{gathered}[/tex]Then our probability is:
[tex]P(X>131.9)=P(Z>1.5147)[/tex]Looking on a table for the value of the probability we have that:
[tex]P(X>131.9)=P(Z>1.5147)=0.0649[/tex]Therefore the probability is 0.0649; which is the same as 6.49%.