There are 55 calories in one originalOreo cookie and 90 calories in oneTriple Double version. Find the numberof calories in one wafer and one layer offilling.I have to solve Algebraically using linear systems

Respuesta :

Let the calories in one wafer be w and calories in one filling be f.

The normal oreo has one filling and 2 wafers and it is given that the number of calories is 55 so it follows:

[tex]2w+f=55\ldots(i)[/tex]

It is also given that the triple double version has 90 calories.

The triple double version has 3 wafers and 2 fillings so it follows:

[tex]3w+2f=90\ldots(ii)[/tex]

Multiply the first equation with 2 to get:

[tex]4w+2f=110\ldots(iii)[/tex]

Subtract (ii) from (iii) to get:

[tex]w=110-90=20[/tex]

Substitute the value w=20 in (i) to get:

[tex]\begin{gathered} 2w+f=55 \\ 2(20)+f=55 \\ f=55-40 \\ f=15 \end{gathered}[/tex]

So the value of f is 15 and w is 20.

Hence one wafer has 20 calories and one layer of filling has 15 calories.

ACCESS MORE
EDU ACCESS