Question

A normal distribution of BMCC MAT51 scores has a standard deviation of 2. Find the z-scores corresponding to each of the following values: (Round to 2 decimal places)a. A score that is 4 points above the mean. (Hint: "x - mean = 5" is 5 above the mean) z = b. A score that is 4 points below the mean. z = c. A score that is 1.73 points above the mean. z = d. A score that is same as the mean. z=

Answer 1

Given:

standard deviation of 2

Required:

We need to find a, b, c and d

Explanation:

a

A score that is 4 points above the mean

$Z=\frac{\mu+4-\mu}{2}=2$

b

$Z=\frac{\mu-4-\mu}{2}=-2$

c

$Z=\frac{\mu+1.73-\mu}{2}=0.87$

d

$Z=\frac{\mu-\mu}{2}=0$

Final answer:

a: z=2

b: z=-2

c: z=0.87

d: z=0