I need the answer to this at least 3 decimal points

The sum of angles of any triangle is 180 degrees
From the given figure
Since mSince m
Then subtract them from 180 degrees to find m[tex]\begin{gathered} m\angle B=180-90-53 \\ m\angle B=\mathring{37} \end{gathered}[/tex]
The measure of angle B is 37 degrees
By using the trigonometry ratios we can find the lengths of AB and BC
Since the opposite side of Since the adjacent side of
We can use the tan C to find AB
[tex]\begin{gathered} \tan C=\frac{opp.}{\text{adj.}} \\ \tan C=\frac{AB}{AC} \end{gathered}[/tex]Since Since AC = 13
[tex]\tan 53=\frac{AB}{13}[/tex]By using cross multiplication
[tex]\begin{gathered} AB=13\times\tan 53 \\ AB=17.25158268 \end{gathered}[/tex]Round it to 3 decimal places, then
AB = 17.252
Since BC is the hypotenuse of the triangle, then
We can use the cos ratio to find it
Since cos = adjacent/hypotenuse, then
[tex]\begin{gathered} \cos C=\frac{AC}{BC} \\ \cos 53=\frac{13}{BC} \end{gathered}[/tex]By using the cross multiplication
[tex]BC\times\cos 53=13[/tex]Divide both sides by cos 53
[tex]\begin{gathered} BC=\frac{13}{\cos 53} \\ BC=21.60132183 \end{gathered}[/tex]Round it to 3 decimal places, then
BC = 21.601