Question

A closed container has 3.06.10to the power of 23 atoms of a gas each atoms of the gas weight

Answer 1

Given: The container contained

$\begin{gathered} 3.06\times10^{23}atoms \\ each\text{ atom weighs} \\ 1.67\times10^{-24} \end{gathered}$

To Determine: The total mass in grams of all the atoms

Solution

$\begin{gathered} If \\ 1atom=1.67\times10^{-24} \end{gathered}$

Then

$3.06\times10^{23}atoms=3.06\times10^{23}\times1.67\times10^{-24}$$\begin{gathered} 3.06\times10^{23}=3.06\times1.67\times10^{23}\times10^{-24} \\ =5.1102\times10^{23-24} \\ =5.1102\times10^{-1}grams \end{gathered}$$=0.51grams$

Hence, the total mass in grams of all the atoms is 0.51 grams because (3.06 x 10²³) x (1.67 x 10⁻²⁴), OPTION B