Question

The equation of OC is (x-5²) +(y+3)² = 9. Of the points P(2,- 1),Q(2,- 6), R(5,-2), and S(7,9), which point is located inside the circle? A. P(2,- 1) B.Q(2-6) C. R(5.-2) D. S(7,0)

Answer 1

Given equation of the circle is

$(x-5)^2+(y+3)^2=9$

Now, for the point P,

$\begin{gathered} (2-5)^2+(-1+3)^2=9+4 \\ =13>9 \end{gathered}$

For the point Q,

$\begin{gathered} (2-5)^2+(-6+3)^2=9+9 \\ =18>9 \end{gathered}$

For the point R,

$(5-5)^2+(-2+3)^2=1<9$

Hence, the point R is inside the circle.

So, the correct answer is (c)