Given data
*The given mass of the bject is m = 20 kg
*The force exerted to the right of the object is F_1 = 55 N
*The force exerted to the left of the object is F_2 = 23 N
The net force acting on the object is calculated as
[tex]\begin{gathered} F_{net}=F_1-F_2 \\ =(55)-(23) \\ =32\text{ N} \end{gathered}[/tex]The formula for the acceleration of the object is given as
[tex]a=\frac{F_{net}}{m}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} a=\frac{32}{20} \\ =1.6m/s^2 \end{gathered}[/tex]Hence, the acceleration of the object is 1.6 m/s^2 and the direction of the acceleration is towards the right direction.