Let's use the variable x to represent the cost of the rice, y to represent the cost of the chicken and z to represent the cost of the eggroll.
2 rices and 1 chicken cost $5, so:
[tex]2x+y=5[/tex]1 rice, 1 chicken and 1 egg cost $5.25, so:
[tex]x+y+z=5.25[/tex]2 chickens and 1 egg cost $5.75, so:
[tex]2y+z=5.75[/tex]From the first equation, we have y = 5 - 2x. Using this value on the other two equations, we have:
[tex]\begin{gathered} x+(5-2x)+z=5.25\\ \\ -x+z=0.25\\ \\ \\ \\ 2(5-2x)+z=5.75\\ \\ -4x+z=-4.25 \end{gathered}[/tex]From the new second equation, we have x = z - 0.25. Using this value in the new third equation, we have:
[tex]\begin{gathered} -4(z-0.25)+z=-4.25\\ \\ -4z+1+z=-4.25\\ \\ -3z=-5.25\\ \\ z=1.75 \end{gathered}[/tex]Therefore the cost of 1 eggroll is $1.75.