Question

I am not sure how to do this and I don’t have much time before my test solve problem a

Answer 1

Given:

a)

Consider the triangles ABC and ADC.

AB=DC

$\angle\text{ABC}=\angle\text{ADC}$

The common side is AC.

Using the two-column method.

$1.AB=DCand\angle ABC=\angle ADC\ldots\ldots\ldots.1.\text{given}$$2.AC\cong AC\ldots\ldots.2.\text{Reflexive property }$$3.\Delta\text{ABC}\cong\Delta ADC\ldots\ldots.3.\text{SAS potulates}$

b)

Consider the triangle.

$1.\angle DEF\cong\angle KJLandDE=JL\ldots\ldots1.given$

Using triangle sum property, we get

$\angle EDF+\angle EFD+\angle DEF=180^o$

$\angle EDF+70^o+60^o=180^o$$\angle E\text{DF}=50^o$$2.\angle EDE\cong\angle JLK\ldots\ldots..2.triangel\text{ sum property.}$$3.\Delta\text{DEF}\cong\Delta\text{KJL}\ldots\ldots\text{.}\mathrm{}\text{ASA postulates}$