The given point is
A(-2,5)
After translation, we get
[tex]A^{\prime}(3,-1)_{}[/tex]Let us consider the translation point as follows:
[tex]A^{\prime}(3,-1)_{}=A^{\prime}(-2+a,5+b)[/tex]It can be written as follows:
[tex](3,-1)_{}=(-2+a,5+b)[/tex][tex]3=-2+a\text{ , -1=5+b}[/tex][tex]3+2=a\text{ , -1-5=b}[/tex][tex]5=a\text{ , -6=b}[/tex][tex]a=5\text{ , b}=-6[/tex]The translation of B (1,-4) is
[tex]B^{\prime}(1+a,-4+b)[/tex]Substitute values, we get
[tex]B^{\prime}(1+a,-4+b)=B^{\prime}(1+5,-4-6)[/tex][tex]=B^{\prime}(6,-10)[/tex]The translation is performed on B(1, -4) to produce
[tex]B^{\prime}(6,-10)[/tex]Option C) is correct.