How much heat is needed to vaporize 10.0 kg of mercury At it’s boiling point?A temperature of a 0.25 kg sample of copper decreases from 75.0 °C to 25.0 °C. How much heat flows out of the copper sample?

How much heat is needed to vaporize 100 kg of mercury At its boiling pointA temperature of a 025 kg sample of copper decreases from 750 C to 250 C How much heat class=

Respuesta :

Given data

*The given mass of mercury is m = 10.0 kg

*The value of latent heat of vaporization of mercury is

[tex]L_v=2.7\times10^5\text{ J/kg}[/tex]

The formula for the heat is needed to vaporize 10.0 kg of mercury at its boiling point is given as

[tex]Q=mL_v[/tex]

Substitute the known values in the above expression as

[tex]\begin{gathered} Q=(10.0)(2.7\times10^5) \\ =2.7\times10^6\text{ J} \end{gathered}[/tex]

Hence, the heat is needed to vaporize 10.0 kg of mercury at its boiling point is Q = 2.7 × 10^6 J

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