How much heat is needed to vaporize 10.0 kg of mercury At it’s boiling point?A temperature of a 0.25 kg sample of copper decreases from 75.0 °C to 25.0 °C. How much heat flows out of the copper sample?

Given data
*The given mass of mercury is m = 10.0 kg
*The value of latent heat of vaporization of mercury is
[tex]L_v=2.7\times10^5\text{ J/kg}[/tex]The formula for the heat is needed to vaporize 10.0 kg of mercury at its boiling point is given as
[tex]Q=mL_v[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} Q=(10.0)(2.7\times10^5) \\ =2.7\times10^6\text{ J} \end{gathered}[/tex]Hence, the heat is needed to vaporize 10.0 kg of mercury at its boiling point is Q = 2.7 × 10^6 J