1. Supposing the equation is ax^2+bx+c
2.
5x^2 - 3x - 12 = 0
Apply the quadratic formula:
[tex]\frac{-b\pm\sqrt[]{b^2-4\cdot a\cdot c}}{2\cdot a}[/tex]ax^2 +bx+c=0
For the equation given:
a = 5
b= -3
c= -12
Replacing:
[tex]\frac{-(-3)\pm\sqrt[]{(-3)^2-4\cdot5\cdot-12}}{2\cdot5}[/tex][tex]\frac{3\pm\sqrt[]{9+240}}{10}[/tex][tex]\frac{3\pm\sqrt[]{249}}{10}[/tex][tex]\frac{3+\sqrt[]{249}}{10}\text{ and }\frac{3-\sqrt[]{249}}{10}[/tex]Solutions in decimals:
x = 1.878 , x = -1.278