Respuesta :

Solution:

Given the graph;

[tex]C=(3,-2),r=\sqrt{26}[/tex]

The equation of a circle is;

[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \\ h=3,k=-2 \\ \end{gathered}[/tex]

Thus;

[tex](x-3)^2+(y+2)^2=26[/tex]

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