Answer:
The Total Surface Area of the Prism is;
[tex]706.4ft^2[/tex]
Explanation:
Given the Prism in the attached image;
We want to find the total surface area T;
[tex]T=(a+b+c+d)l+(a+c)h[/tex]
where;
[tex]\begin{gathered} a,b,c,d\text{ are the sides of the trapezium} \\ a=19ft \\ b=14ft \\ c=5ft \\ d=14ft \\ l=\text{length} \\ l=8ft \\ h=\text{height of trapezium} \\ h=12.1ft \end{gathered}[/tex]
Substituting the given values;
[tex]\begin{gathered} T=(a+b+c+d)l+(a+c)h \\ T=(19+14+5+14)8+(19+5)12.1 \\ T=(52)8+(24)12.1 \\ T=416+290.4 \\ T=706.4ft^2 \end{gathered}[/tex]
Therefore, the Total Surface Area of the Prism is;
[tex]706.4ft^2[/tex]
