Question

The graph shows the current through a 4.7 ohm resistor as a function of time. What is the total energy dissipated through this resistor in 5 seconds.

Answer 1

$P=VI$

where:

$\begin{gathered} V=IR \\ so: \\ P=I^2R \end{gathered}$

For t = 5:

$\begin{gathered} I=1A \\ so: \\ P=1^2\cdot4.7 \\ P=4.7W \\ Therefore: \\ E=P\cdot t \\ E=4.7W\cdot5s \\ E=23.5J \end{gathered}$

Answer:

23.5 J